Physics · 2021
JEE Main · 25 July 2021, Shift 2 · Q11
If q_f is the free charge on the capacitor plates and q_b is the bound charge on the dielectric slab of dielectric constant k placed between the…
If $\displaystyle q_f$ is the free charge on the capacitor plates and $\displaystyle q_b$ is the bound charge on the dielectric slab of dielectric constant $\displaystyle k$ placed between the capacitor plates, then bound charge $\displaystyle q_b$ can be expressed as:
Official answer
(1)
$\displaystyle q_b=q_f\left(1-\frac{1}{k}\right)$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.