Employing a resistance of 8 Ω, a capacitor is charged through a battery of 12 V. In 2 μ s time, the potential difference across the capacitor is…

Employing a resistance of $\displaystyle 8 \Omega$, a capacitor is charged through a battery of $\displaystyle 12$ V . In $\displaystyle 2 \mu \mathrm{~s}$ time, the potential difference across the capacitor is found to be $\displaystyle 6$ V .The storage capacity of the capacitor is $\displaystyle \frac{x}{100} \mu F$. Then the value of $\displaystyle x$ is \_\_\_\_. $$(\ln 2=0.69) $$