Physics · 2013
JEE Main · 23 April 2013, Shift 1 · Q6
Electrons are accelerated through a potential difference V and protons are accelerated through a potential difference 4 V. The de-Broglie wavelengths…
Electrons are accelerated through a potential difference V and protons are accelerated through a potential difference $\displaystyle 4$ V . The de-Broglie wavelengths are $\displaystyle \lambda_{\mathrm{e}}$ and $\displaystyle \lambda_p$ for electrons and protons respectively. The ratio of $\displaystyle \frac{\lambda_{\mathrm{e}}}{\lambda_{\mathrm{p}}}$ is given by : (given $\displaystyle \mathrm{m}_{\mathrm{e}}$ is mass of electron and $\displaystyle \mathrm{m}_{\mathrm{p}}$ is mass of proton).
Official answer
(4)
$\displaystyle \frac{\lambda_{\mathrm{e}}}{\lambda_{\mathrm{p}}}=2 \sqrt{\frac{m_{\mathrm{p}}}{m_{\mathrm{e}}}}$
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JEE Main 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.