The electric field at a point associated with a light wave is given by E=200[ sin (6 × 10^15) t+ sin (9 × 10^15) t] Vm^-1 Given: h=4.14 × 10^-15 eVs…

The electric field at a point associated with a light wave is given by $$E=200\left[\sin \left(6 \times 10^{15}\right) t+\sin \left(9 \times 10^{15}\right) t\right] \mathrm{Vm}^{-1} $$Given : $\displaystyle h=4.14 \times 10^{-15} \mathrm{eVs}$ If this light falls on a metal surface having a work function of $\displaystyle 2.50 e V$, the maximum kinetic energy of the photoelectrons will be