Physics · 2019
JEE Main · 8 April 2019, Shift 1 · Q26
Two particles move at right angle to each other. Their de Broglie wavelengths are λ_1 and λ_2 respectively. The particles suffer perfectly inelastic…
Two particles move at right angle to each other. Their de Broglie wavelengths are $\displaystyle \lambda_1$ and $\displaystyle \lambda_2$ respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength $\displaystyle \lambda$, of the final particle, is given by:
Official answer
(4)
$\displaystyle \frac{1}{\lambda^2}=\frac{1}{\lambda_1^2}+\frac{1}{\lambda_2^2}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.