Physics · 2021
JEE Main · 26 February 2021, Shift 1 · Q14
An alternating current is given by the equation i=i_1 sin ω t +i_2 cos ω t. The rms current will be:
An alternating current is given by the equation $\displaystyle i=i_1 \sin \omega \mathrm{t}+i_2 \cos \omega \mathrm{t}$. The rms current will be:
Official answer
(3)
$\displaystyle \frac{1}{\sqrt{2}}\left(i_1^2+i_2^2\right)^{\frac{1}{2}}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.