Physics · 2021
JEE Main · 17 March 2021, Shift 1 · Q7
An AC current is given by I = I_1 sin ω t + I_2 cos ω t. A hot wire ammeter will give a reading:
An AC current is given by $\displaystyle \mathrm{I}=\mathrm{I}_1 \sin \omega \mathrm{t}+\mathrm{I}_2 \cos \omega \mathrm{t}$. A hot wire ammeter will give a reading :
Official answer
(3)
$\displaystyle \sqrt{\frac{I_1^2+I_2^2}{2}}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.