Physics · 2024
JEE Main · 9 April 2024, Shift 1 · Q60
A star has 100% helium composition. It starts to convert three ^4 He into one ^12 C via triple alpha process as ^4 He +^4 He +^4 He →^12 C + Q. The…
A star has $\displaystyle 100$% helium composition. It starts to convert three $\displaystyle { }^4 \mathrm{He}$ into one $\displaystyle { }^{12} \mathrm{C}$ via triple alpha process as $\displaystyle { }^4 \mathrm{He}+{ }^4 \mathrm{He}+{ }^4 \mathrm{He} \rightarrow{ }^{12} \mathrm{C}+\mathrm{Q}$. The mass of the star is $\displaystyle 2.0 \times 10^{32} \mathrm{~kg}$ and it generates energy at the rate of $\displaystyle 5.808 \times 10^{30} \mathrm{~W}$. The rate of converting these $\displaystyle { }^4 \mathrm{He}$ to $\displaystyle { }^{12} \mathrm{C}$ is $\displaystyle \mathrm{n} \times 10^{42} \mathrm{~s}^{-1}$, where n is $\displaystyle \_\_\_\_$.
[ Take, mass of $\displaystyle { }^4 \mathrm{He}=4.0026 \mathrm{u}$, mass of $\displaystyle { }^{12} \mathrm{C}=12 \mathrm{u}$ ]
Official answer
From NTA’s final answer key for this paper.
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.