Physics · 2022
JEE Main · 26 July 2022, Shift 2 · Q45
A source of potential difference V is connected to the combination of two identical capacitors as shown in the figure. When key ' K ' is closed, the…
A source of potential difference $\displaystyle V$ is connected to the combination of two identical capacitors as shown in the figure. When key ' $\displaystyle K$ ' is closed, the total energy stored across the combination is $\displaystyle E_1$. Now key ' $\displaystyle K$ ' is opened and dielectric of dielectric constant $\displaystyle 5$ is introduced between the plates of the capacitors. The total energy stored across the combination is now $\displaystyle E_2$. The ratio $\displaystyle E_1 / E_2$ will be :
Official answer
(3)
$\displaystyle \frac{5}{13}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.