Physics · 2026
JEE Main · 28 January 2026, Shift 2 · Q29
A small block of mass m slides down from the top of a frictionless inclined surface, while the inclined plane is moving towards left with constant…
A small block of mass $\displaystyle m$ slides down from the top of a frictionless inclined surface, while the inclined plane is moving towards left with constant acceleration $\displaystyle a_0$. The angle between the inclined plane and ground is $\displaystyle \theta$ and its base length is $\displaystyle L$. Assuming that initially the small block is at the top of the inclined plane, the time it takes to reach the lowest point of the inclined plane is $\displaystyle \_\_\_\_$.

Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \sqrt{\frac{4 L}{g \sin 2 \theta-a_0(1+\cos 2 \theta)}}$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.