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Physics · 2026

JEE Main · 5 April 2026, Shift 1 · Q29

Three masses m_1=4 kg, m_2=4 kg and m_3=6 kg are suspended from a fixed smooth frictionless pully as shown in the figure below. The value of T_1 /…

Three masses $\displaystyle m_1=4 \mathrm{~kg}, m_2=4 \mathrm{~kg}$ and $\displaystyle m_3=6 \mathrm{~kg}$ are suspended from a fixed smooth frictionless pully as shown in the figure below. The value of $\displaystyle \mathrm{T}_1 / \mathrm{T}_2$ is $\displaystyle \_\_\_\_$ (take $\displaystyle g=10 \mathrm{~m} / \mathrm{s}^2$ ) Figure: JEE Main Physics 2026, Newton's Laws of Motion
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.