A wedge Y with mass of 10 kg and all frictionless surfaces and the inclined surface making 37^° with horizontal. A block X with mass 2 kg is placed…

A wedge $\displaystyle Y$ with mass of $\displaystyle 10$ kg and all frictionless surfaces and the inclined surface making $\displaystyle 37^{\circ}$ with horizontal. A block $\displaystyle X$ with mass $\displaystyle 2$ kg is placed at the highest point of the wedge as shown in figure is at rest. At $\displaystyle t=0$ wedge $\displaystyle (Y)$ is pulled toward right with constant force $\displaystyle (f)$ of $\displaystyle 24$ N. Taking the block $\displaystyle X$ at rest at $\displaystyle t=0$, the time taken by it to slide down $\displaystyle 8.8$ m on the slope, while $\displaystyle Y$ is on the move, is $\displaystyle \_\_\_\_$ s. (take $\displaystyle \tan \left(37^{\circ}\right)=3 / 4$ and $\displaystyle \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )