Physics · 2022
JEE Main · 28 July 2022, Shift 2 · Q9
A slab of dielectric constant K has the same cross-sectional area as the plates of a parallel plate capacitor and thickness 3/4 d, where d is the…
A slab of dielectric constant K has the same cross-sectional area as the plates of a parallel plate capacitor and thickness $\displaystyle \frac{3}{4} \mathrm{~d}$, where d is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be:
(Given $\displaystyle \mathrm{C}_{\mathrm{o}}=$ capacitance of capacitor with air as medium between plates.)
Official answer
(1)
$\displaystyle \frac{4 K C_0}{3+K}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.