SolveIt is under development
SolveItJEE Main
Question 115 / 128 · latest first
Physics · 2021

JEE Main · 16 March 2021, Shift 1 · Q21

A sinusoidal voltage of peak value 250 V is applied to a series LCR circuit, in which R =8 Ω, L =24 mH and C =60 μ F. The value of power dissipated…

A sinusoidal voltage of peak value $\displaystyle 250$ V is applied to a series LCR circuit, in which $\displaystyle \mathrm{R}=8 \Omega$, $\displaystyle \mathrm{L}=24 \mathrm{mH}$ and $\displaystyle \mathrm{C}=60 \mu \mathrm{~F}$. The value of power dissipated at resonant condition is '$\displaystyle x$' $\displaystyle \mathrm{kW}$. The value of $\displaystyle x$ to the nearest integer is \_\_\_\_.
ShareWhatsAppTelegram

More from Alternating Current

JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.