Physics · 2022
JEE Main · 27 July 2022, Shift 2 · Q44
A series LCR circuit has L =0.01 H, R =10 Ω and C =1 μ F and it is connected to ac voltage of amplitude ( V_m ) 50 V. At frequency 60% lower than…
A series LCR circuit has $\displaystyle \mathrm{L}=0.01 \mathrm{H}, \mathrm{R}=10 \Omega$ and $\displaystyle \mathrm{C}=1 \mu \mathrm{~F}$ and it is connected to ac voltage of amplitude $\displaystyle \left(\mathrm{V}_{\mathrm{m}}\right) 50 \mathrm{~V}$. At frequency $\displaystyle 60$% lower than resonant frequency, the amplitude of current will be approximately :
Official answer
(3)
$\displaystyle 238$ mA
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.