Physics · 2019
JEE Main · 9 January 2019, Shift 2 · Q18
A series AC circuit containing an inductor (20 mH ), a capacitor (120 μ F ) and a resistor ( 60 Ω ) is driven by an AC source of 24 V / 50 Hz. The…
A series AC circuit containing an inductor $\displaystyle (20 \mathrm{mH})$, a capacitor $\displaystyle (120 \mu \mathrm{~F})$ and a resistor ( $\displaystyle 60 \Omega$ ) is driven by an AC source of $\displaystyle 24 \mathrm{~V} / 50 \mathrm{~Hz}$. The energy dissipated in the circuit in $\displaystyle 60$ s is :
Official answer
(3)
$\displaystyle 5.17 \times 10^2 \mathrm{~J}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.