Physics · 2021
JEE Main · 26 August 2021, Shift 2 · Q18
A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant K_1 and K_2 of same…
A parallel-plate capacitor with plate area A has separation d between the plates. Two dielectric slabs of dielectric constant $\displaystyle \mathrm{K}_1$ and $\displaystyle \mathrm{K}_2$ of same area A/$\displaystyle 2$ and thickness d/$\displaystyle 2$ are inserted in the space between the plates. The capacitance of the capacitor will be given by :
Official answer
(4)
$\displaystyle \frac{\varepsilon_0 \mathrm{~A}}{\mathrm{~d}}\left(\frac{1}{2}+\frac{\mathrm{K}_1 \mathrm{~K}_2}{\mathrm{~K}_1+\mathrm{K}_2}\right)$
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