Physics · 2018
JEE Main · 15 April 2018, Shift 2 · Q15
A parallel plate capacitor with area 200 cm^2 and separation between the plates 1.5 cm, is connected across a battery of emf V. If the force of…
A parallel plate capacitor with area $\displaystyle 200 \mathrm{~cm}^2$ and separation between the plates $\displaystyle 1.5$ cm, is connected across a battery of emf V. If the force of attraction between the plates is $\displaystyle 25 \times 10^{-6} \mathrm{~N}$, the value of V is approximately :
$$\left(\epsilon_{\mathrm{o}}=8.85 \times 10^{-12} \frac{\mathrm{C}^2}{\mathrm{~N} . \mathrm{m}^2}\right)
$$
Official answer
(1)
$\displaystyle 250 \mathrm{~V}$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.