Physics · 2014
JEE Main · 11 April 2014, Shift 1 · Q17
A parallel plate capacitor is made of two plates of length l, width w and separated by distance d. A dielectric slab (dielectric constant K) that…
A parallel plate capacitor is made of two plates of length $\displaystyle l$, width $\displaystyle w$ and separated by distance $\displaystyle d$. A dielectric slab (dielectric constant K) that fits exactly between the plates is held near the edge of the plates. It is pulled into the capacitor by a force $\displaystyle \mathrm{F}=-\frac{\partial \mathrm{U}}{\partial x}$ where U is the energy of the capacitor when dielectric is inside the capacitor up to distance $\displaystyle x$ (See figure). If the charge on the capacitor is Q then the force on the dielectric when it is near the edge is :

Official answer
(3)
$\displaystyle \frac{\mathrm{Q}^2 d}{2 w l^2 \epsilon_{\mathrm{o}}}(\mathrm{~K}-1)$
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.