Physics · 2019
JEE Main · 10 January 2019, Shift 2 · Q14
A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging…
A parallel plate capacitor having capacitance $\displaystyle 12$ pF is charged by a battery to a potential difference of $\displaystyle 10$ V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant $\displaystyle 6.5$ is slipped between the plates. The work done by the capacitor on the slab is :
Official answer
(1)
$\displaystyle 508$ pJ
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.