A parallel plate capacitor having a separation between the plates d, plate area A and material with dielectric constant K has capacitance C_0. Now…

A parallel plate capacitor having a separation between the plates d, plate area A and material with dielectric constant K has capacitance $\displaystyle \mathrm{C}_0$. Now one-third of the material is replaced by another material with dielectric constant $\displaystyle 2$ K , so that effectively there are two capacitors one with area $\displaystyle \frac{1}{3} \mathrm{~A}$, dielectric constant $\displaystyle 2$ K and another with area $\displaystyle \frac{2}{3} \mathrm{~A}$ and dielectric constant K. If the capacitance of this new capacitor is C then $\displaystyle \mathrm{C} / \mathrm{C}_0$ is :