Physics · 2019
JEE Main · 8 April 2019, Shift 2 · Q14
A parallel plate capacitor has 1 μ F capacitance. One of its two plates is given +2 μ C charge and the other plate, +4 μ C charge. The potential…
A parallel plate capacitor has $\displaystyle 1 \mu \mathrm{~F}$ capacitance. One of its two plates is given $\displaystyle +2 \mu \mathrm{C}$ charge and the other plate, $\displaystyle +4 \mu \mathrm{C}$ charge. The potential difference developed across the capacitor is :
Official answer
(1)
$\displaystyle 1$ V
More from Capacitors
- Two capacitors of capacities 2 C and C are joined in parallel and charged up to potential V. The battery is removed and the capacitor of capacity C…2021
- Space between the plates of a parallel plate capacitor of plate area 4 cm^2 and separation of 1.77 mm, is filled with uniform dielectric materials…2025
- Two parallel plate capacitors C_1 and C_2 each having capacitance of 10 μ F are individually charged by a 100 V D.C. source. Capacitor C_1 is kept…2023
- Calculate the amount of charge on capacitor of 4 μ F. The internal resistance of battery is 1 Ω:2021
- A parallel plate capacitor of capacitance 200 μ F is connected to a battery of 200 V. A dielectric slab of dielectric constant 2 is now inserted into…2021
- A capacitor P with capacitance 10 × 10^-6 F is fully charged with a potential difference of 6.0 V and disconnected from the battery. The charged…2026
- The charge on capacitor of capacitance 15 μ F in the figure given below is:2022
- Three capacitors of capacitances 25 μ F, 30 μ F and 45 μ F are connected in parallel to a supply of 100 V. Energy stored in the above combination is…2024
JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.