SolveItJEE Main
Physics · 2024

JEE Main · 29 January 2024, Shift 1 · Q52

A cylinder is rolling down on an inclined plane of inclination 60^°. It's acceleration during rolling down will be x/(√ 3) m / s^2, where x= ____…

A cylinder is rolling down on an inclined plane of inclination $\displaystyle 60^{\circ}$. It's acceleration during rolling down will be $\displaystyle \frac{x}{\sqrt{3}} m / s^2$, where $\displaystyle x=$ $\displaystyle \_\_\_\_$ (use $\displaystyle \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ).
ShareWhatsAppTelegram

More from Rotational Motion

JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.