SolveItJEE Main
Physics · 2024

JEE Main · 5 April 2024, Shift 2 · Q52

A hollow sphere is rolling on a plane surface about its axis of symmetry. The ratio of rotational kinetic energy to its total kinetic energy is x/5.…

A hollow sphere is rolling on a plane surface about its axis of symmetry. The ratio of rotational kinetic energy to its total kinetic energy is $\displaystyle \frac{x}{5}$. The value of $\displaystyle x$ is $\displaystyle \_\_\_\_$.
ShareWhatsAppTelegram

More from Rotational Motion

JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.