Physics · 2019
JEE Main · 8 April 2019, Shift 2 · Q21
A circuit connected to an ac source of emf e = e_0 sin (100 t ) with t in seconds, gives a phase difference of (π)/4 between the emf e and current i.…
A circuit connected to an ac source of emf $\displaystyle \mathrm{e}=\mathrm{e}_0 \sin (100 \mathrm{t})$ with t in seconds, gives a
phase difference of $\displaystyle \frac{\pi}{4}$ between the emf e and current i. Which of the following circuits will exhibit this ?
Official answer
(2)
$\displaystyle \begin{aligned}
& \mathrm{RC} \text { circuit with } \mathrm{R}=1 \mathrm{k} \Omega \text { and } \\
& \mathrm{C}=10 \mu \mathrm{~F}
\end{aligned}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.