Physics · 2019
JEE Main · 9 April 2019, Shift 1 · Q15
A capacitor with capacitance 5 μ F is charged to 5 μ C. If the plates are pulled apart to reduce the capacitance to 2 μ F, how much work is done?
A capacitor with capacitance $\displaystyle 5 \mu \mathrm{~F}$ is charged to $\displaystyle 5 \mu \mathrm{C}$. If the plates are pulled apart to reduce the capacitance to $\displaystyle 2 \mu \mathrm{~F}$, how much work is done ?
Official answer
(4)
$\displaystyle 3.75 \times 10^{-6} \mathrm{~J}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.