Physics · 2021
JEE Main · 27 July 2021, Shift 1 · Q4
A capacitor of capacitance C =1 μ F is suddenly connected to a battery of 100 volt through a resistance R =100 Ω. The time taken for the capacitor to…
A capacitor of capacitance $\displaystyle \mathrm{C}=1 \mu \mathrm{~F}$ is suddenly connected to a battery of $\displaystyle 100$ volt through a resistance $\displaystyle \mathrm{R}=100 \Omega$. The time taken for the capacitor to be charged to get $\displaystyle 50$ V is :
$\displaystyle [$ Take $\displaystyle \ln 2=0.69]$Official answer
(1)
$\displaystyle 0.69 \times 10^{-4} \mathrm{~s}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.