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Physics · 2022

JEE Main · 27 June 2022, Shift 1 · Q57

A capacitor of capacitance 50 pF is charged by 100 V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss…

A capacitor of capacitance $\displaystyle 50$ pF is charged by $\displaystyle 100$ V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is \_\_\_\_ nJ.
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.