Physics · 2020
JEE Main · 2 September 2020, Shift 2 · Q11
A 10 μ F capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in…
A $\displaystyle 10 \mu \mathrm{~F}$ capacitor is fully charged to a potential difference of $\displaystyle 50$ V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes $\displaystyle 20$ V . The capacitance of the second capacitor is :
Official answer
(1)
$\displaystyle 15 \mu \mathrm{~F}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.