Physics · 2021
JEE Main · 17 March 2021, Shift 2 · Q21
A 2 μ F capacitor C_1 is first charged to a potential difference of 10 V using a battery. Then the battery is removed and the capacitor is connected…
A $\displaystyle 2 \mu \mathrm{~F}$ capacitor $\displaystyle \mathrm{C}_1$ is first charged to a potential difference of $\displaystyle 10$ V using a battery. Then the battery is removed and the capacitor is connected to an uncharged capacitor $\displaystyle \mathrm{C}_2$ of $\displaystyle 8 \mu \mathrm{~F}$. The charge in $\displaystyle \mathrm{C}_2$ on equilibrium condition is \_\_\_\_ $\displaystyle \mu \mathrm{C}$. (Round off to the Nearest Integer)
Official answer
16
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