A capacitor C_1=1.0 μ F is charged up to a voltage V =60 V by connecting it to battery B through switch (1). Now C_1 is disconnected from battery and…

A capacitor $\displaystyle \mathrm{C}_1=1.0 \mu \mathrm{~F}$ is charged up to a voltage $\displaystyle \mathrm{V}=60 \mathrm{~V}$ by connecting it to battery B through switch ($\displaystyle 1$). Now $\displaystyle \mathrm{C}_1$ is disconnected from battery and connected to a circuit consisting of two uncharged capacitors $\displaystyle \mathrm{C}_2=3.0 \mu \mathrm{~F}$ and $\displaystyle \mathrm{C}_3=6.0 \mu \mathrm{~F}$ through switch ($\displaystyle 2$), as shown in the figure. The sum of final charges on $\displaystyle \mathrm{C}_2$ and $\displaystyle \mathrm{C}_3$ is :