Physics · 2015
JEE Main · 10 April 2015, Shift 1 · Q4
A block of mass m =0.1 kg is connected to a spring of unknown spring constant k. It is compressed to a distance x from its equilibrium position and…
A block of mass $\displaystyle \mathrm{m}=0.1 \mathrm{~kg}$ is connected to a spring of unknown spring constant k . It is compressed to a distance $\displaystyle x$ from its equilibrium position and released from rest.
After approaching half the distance $\displaystyle \left(\frac{x}{2}\right)$ from equilibrium position, it hits another block and comes to rest momentarily, while the other block moves with a velocity $\displaystyle 3 \mathrm{~ms}^{-1}$. The total initial energy of the spring is :
Official answer
(2)
0.$\displaystyle 6$ J
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JEE Main 2015 Physics question, with the answer from NTA’s final answer key. Where our answers come from.