Physics · 2024
JEE Main · 9 April 2024, Shift 1 · Q35
A particle of mass m moves on a straight line with its velocity increasing with distance according to the equation v=α √ x, where α is a constant.…
A particle of mass $\displaystyle m$ moves on a straight line with its velocity increasing with distance according to the equation $\displaystyle v=\alpha \sqrt{x}$, where $\displaystyle \alpha$ is a constant. The total work done by all the forces applied on the particle during its displacement from $\displaystyle x=0$ to $\displaystyle x=\mathrm{d}$, will be :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{m \alpha^2 d}{2}$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.