Physics · 2019
JEE Main · 9 January 2019, Shift 2 · Q5
A force acts on a 2 kg object so that its position is given as a function of time as x=3 t^2+5. What is the work done by this force in first 5…
A force acts on a $\displaystyle 2$ kg object so that its position is given as a function of time as $\displaystyle x=3 \mathrm{t}^2+5$. What is the work done by this force in first $\displaystyle 5$ seconds?
Official answer
(2)
$\displaystyle 900$ J
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.