Physics · 2013
JEE Main · 23 April 2013, Shift 1 · Q26
A 70 kg man leaps vertically into the air from a crouching position. To take the leap the man pushes the ground with a constant force F to raise…
A $\displaystyle 70$ kg man leaps vertically into the air from a crouching position. To take the leap the man pushes the ground with a constant force F to raise himself. The center of gravity rises by $\displaystyle 0.5$ m before he leaps. After the leap the c.g. rises by another $\displaystyle 1$ m . The maximum power delivered by the muscles is : (Take $\displaystyle \mathrm{g}=10 \mathrm{~ms}^{-2}$ ).
Official answer
(2)
$\displaystyle 6.26 \times 10^3$ Watts at take off
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JEE Main 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.