Physics · 2026
JEE Main · 22 January 2026, Shift 1 · Q43
9 MeV α -particle scatters from a target material of atomic number 79. From the given data the estimated diameter of nuclei of the target material is…
$\displaystyle 9$ MeV $\displaystyle \alpha$-particle scatters from a target material of atomic number 79. From the given data the estimated diameter of nuclei of the target material is (approximately) $\displaystyle \_\_\_\_$ m.
$$\left[\frac{1}{4 \pi \epsilon_{\mathrm{o}}}=9 \times 10^9 \mathrm{Nm}^2 / \mathrm{C}^2 \text { and electron charge }=1.6 \times 10^{-19} \mathrm{C}\right]
$$
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 5.76 \times 10^{-14}$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.