Two lines (x-3)/1=(y+1)/3=(z-6)/-1 and (x+5)/7=(y-2)/-6=(z-3)/4 intersect at the point R. The reflection of R in the x y -plane has coordinates:

Two lines $\displaystyle \frac{x-3}{1}=\frac{y+1}{3}=\frac{z-6}{-1} \quad$ and $\displaystyle \frac{x+5}{7}=\frac{y-2}{-6}=\frac{z-3}{4}$ intersect at the point R . The reflection of R in the $\displaystyle x y$-plane has coordinates :