Mathematics · 2021
JEE Main · 17 March 2021, Shift 1 · Q70
The value of lim_x → 0^+ (cos^-1(x-[x]^2) · sin^-1(x-[x]^2))/(x-x^3), where [x] denotes the greatest integer ≤ x is:
The value of $\displaystyle \lim _{x \rightarrow 0^{+}} \frac{\cos ^{-1}\left(x-[x]^2\right) \cdot \sin ^{-1}\left(x-[x]^2\right)}{x-x^3}$, where $\displaystyle [x]$ denotes the greatest integer $\displaystyle \leq x$ is :
Official answer
(3)
$\displaystyle \frac{\pi}{2}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.