Mathematics · 2022
JEE Main · 26 June 2022, Shift 1 · Q28
The value of the integral 48/(π^4) ∫_0^π((3 π x^2)/2-x^3) (sin x)/(1+ cos^2 x) d x is equal to \ \ \ \.
The value of the integral $\displaystyle \frac{48}{\pi^4} \int_0^\pi\left(\frac{3 \pi x^2}{2}-x^3\right) \frac{\sin x}{1+\cos ^2 x} \mathrm{~d} x$ is equal to \_\_\_\_.
Official answer
6
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.