Mathematics · 2022
JEE Main · 25 June 2022, Shift 2 · Q12
If b_n=∫_0^((π)/2) (cos^2 n x)/(sin x) d x, n ∈ N, then
If $\displaystyle b_n=\int_0^{\frac{\pi}{2}} \frac{\cos ^2 n x}{\sin x} d x, n \in \mathbb{N}$, then
Official answer
(4)
$\displaystyle \frac{1}{b_3-b_2}, \frac{1}{b_4-b_3}, \frac{1}{b_5-b_4}$ are in an A.P. with common difference -$\displaystyle 2$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.