Mathematics · 2020
JEE Main · 3 September 2020, Shift 2 · Q61
If the value of the integral ∫_0^1 / 2 x^2/((1-x^2)^3 / 2) d x is k/6, then k is equal to:
If the value of the integral
$$\int_0^{1 / 2} \frac{x^2}{\left(1-x^2\right)^{3 / 2}} \mathrm{~d} x
$$
is $\displaystyle \frac{\mathrm{k}}{6}$, then k is equal to :
Official answer
(2)
$\displaystyle 2 \sqrt{3}-\pi$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.