Mathematics · 2024
JEE Main · 9 April 2024, Shift 2 · Q12
The value of the integral ∫_-1^2 log_e(x+√(x^2+1)) d x is
The value of the integral $\displaystyle \int_{-1}^2 \log _e\left(x+\sqrt{x^2+1}\right) d x$ is
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \sqrt{2}-\sqrt{5}+\log _e\left(\frac{9+4 \sqrt{5}}{1+\sqrt{2}}\right)$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.