If ( a, b ) be the orthocentre of the triangle whose vertices are (1,2),(2,3) and (3,1), and I_1=∫_a^b x sin (4 x-x^2) d x, I_2=∫_a^b sin (4 x-x^2) d…

If $\displaystyle (\mathrm{a}, \mathrm{b})$ be the orthocentre of the triangle whose vertices are $\displaystyle (1,2),(2,3)$ and $\displaystyle (3,1)$, and $\displaystyle \mathrm{I}_1=\int_{\mathrm{a}}^{\mathrm{b}} x \sin \left(4 x-x^2\right) \mathrm{d} x, \mathrm{I}_2=\int_{\mathrm{a}}^{\mathrm{b}} \sin \left(4 x-x^2\right) \mathrm{d} x$, then $\displaystyle 36 \frac{\mathrm{I}_1}{\mathrm{I}_2}$ is equal to :