Mathematics · 2025
JEE Main · 22 January 2025, Shift 1 · Q18
Let for f(x)=7 tan^8 x+7 tan^6 x-3 tan^4 x-3 tan^2 x, I_1=∫_0^π / 4 f(x) d x and I_2=∫_0^π / 4 x f(x) d x. Then 7 I_1+12 I_2 is equal to:
Let for $\displaystyle f(x)=7 \tan ^8 x+7 \tan ^6 x-3 \tan ^4 x-3 \tan ^2 x, \mathrm{I}_1=\int_0^{\pi / 4} f(x) \mathrm{d} x$ and $\displaystyle \mathrm{I}_2=\int_0^{\pi / 4} x f(x) \mathrm{d} x$. Then $\displaystyle 7 \mathrm{I}_1+12 \mathrm{I}_2$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 1$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.