Mathematics · 2025
JEE Main · 23 January 2025, Shift 1 · Q19
The value of ∫_e^2^e^4 1/x((e^(( log_e x)^2+1)^-1)/(e^(( log_e x)^2+1)^-1 +e^((6- log_e x)^2+1)^-1)) d x is
The value of
$$\int_{e^2}^{e^4} \frac{1}{x}\left(\frac{e^{\left(\left(\log _e x\right)^2+1\right)^{-1}}}{e^{\left(\left(\log _e x\right)^2+1\right)^{-1}}+e^{\left(\left(6-\log _e x\right)^2+1\right)^{-1}}}\right) d x \text { is }
$$
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 1$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.