Mathematics · 2025
JEE Main · 8 April 2025, Shift 2 · Q13
The value of cot^-1((√(1+ tan^2(2))-1)/(tan (2)))- cot^-1((√(1+ tan^2(1/2))+1)/(tan (1/2))) is equal to
The value of $\displaystyle \cot ^{-1}\left(\frac{\sqrt{1+\tan ^2(2)}-1}{\tan (2)}\right)-\cot ^{-1}\left(\frac{\sqrt{1+\tan ^2\left(\dfrac{1}{2}\right)}+1}{\tan \left(\dfrac{1}{2}\right)}\right)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \pi-\frac{5}{4}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.