Mathematics · 2020
JEE Main · 4 September 2020, Shift 1 · Q55
The value of Σ_r =0^20^50- r C_6 is equal to:
The value of $\displaystyle \sum_{\mathbf{r}=0}^{20}{ }^{50-\mathrm{r}} \mathrm{C}_6$ is equal to :
Official answer
(3)
$\displaystyle { }^{51} \mathrm{C}_7-{ }^{30} \mathrm{C}_7$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.