Mathematics · 2020
JEE Main · 4 September 2020, Shift 1 · Q72
Let (2 x^2+3 x+4)^10=Σ_r =0^20 a_r x^r. Then (a_7)/(a_13) is equal to \ \ \ \.
Let $\displaystyle \left(2 x^2+3 x+4\right)^{10}=\sum_{\mathrm{r}=0}^{20} \mathrm{a}_{\mathrm{r}} x^{\mathrm{r}}$. Then $\displaystyle \frac{\mathrm{a}_7}{\mathrm{a}_{13}}$ is equal to \_\_\_\_.
Official answer
8
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.