Mathematics · 2019
JEE Main · 12 April 2019, Shift 1 · Q89
The value of sin^-1(12/13)- sin^-1(3/5) is equal to:
The value of $\displaystyle \sin ^{-1}\left(\frac{12}{13}\right)-\sin ^{-1}\left(\frac{3}{5}\right)$ is equal to :
Official answer
(4)
$\displaystyle \frac{\pi}{2}-\sin ^{-1}\left(\frac{56}{65}\right)$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.