Mathematics · 2023
JEE Main · 1 February 2023, Shift 1 · Q67
The value of 1/(1!50!)+1/(3!48!)+1/(5!46!)+….+1/(49!2!)+1/(51!1!) is:
The value of
$\displaystyle \frac{1}{1!50!}+\frac{1}{3!48!}+\frac{1}{5!46!}+\ldots .+\frac{1}{49!2!}+\frac{1}{51!1!}$ is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{2^{50}}{51!}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.